Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.7 Apply the Fundamental Theorem of Algebra - 5.7 Exercises - Mixed Review - Page 386: 76


$y=\dfrac{1}{2} (x+2)(x-4)$

Work Step by Step

Here, we find the x-intercepts are $-2$ and $4$. Thus, the function is: $y=a (x+2)(x-4)$ Since, $(2,-4)$ is on the graph of this function, we have $-4=a (2+2)(2-4)$ This gives: $-4=-8a \implies a=\dfrac{1}{2}$ Hence, the required function is: $y=\dfrac{1}{2} (x+2)(x-4)$
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