Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Chapter Review - Page 319: 21



Work Step by Step

$2\cdot72\cdot48=(72+x)(48+x)\\6912=3456+x^2+120x\\x^2+120x-3456=0\\(x+144)(x-24)=0$ Thus $x=24$ or $x=−144$ but $x$ has to be positive, thus $x=24$.
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