## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 2 Linear Equations and Functions - 2.5 Model Direct Variation - 2.5 Exercises - Skill Practice - Page 109: 28

#### Answer

$$14\frac{2}{9}$$

#### Work Step by Step

We plug in the given point to find the constant of variation. Since the equation will be for direct variation, we can then plug this in for $a$ in the equation $y=ax$. (Note, the y-intercept is 0). Hence, we find: $$-\frac{15}{8}=\frac{-20}{3} a \\ a=.28125$$ Thus: $$y=.28125x$$ When $y=-4$: $$x=\frac{-4}{.28125} = 14\frac{2}{9}$$

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