Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.2 Define General Angles and Use Radian Measure - 13.2 Exercises - Quiz for Lessons 13.1 and 13.2 - Page 865: 5

Answer

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Work Step by Step

Given: $A=15$ degrees $a=19$ Thus, $C=90$ It is a right triangle. Hence, the sum of two non-right angles of a triangle is 90 degrees: $B=90-B=90-15=75$ degrees We know $\tan B=\frac{b}{a}\\ \rightarrow b=a\tan B=9\times \tan 75\approx 33.59$ Apply the Pythagorean theorem to find c: $a^2+b^2=c^2\\c=\sqrt a^2+b^2\\c=\sqrt 9^2+(9\tan 75)^2\approx 34.77$
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