Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 12 Sequences and Series - Chapter Review - Page 840: 5



Work Step by Step

$a_1=1^2+7=8$ $a_2=2^2+7=11$ $a_3=3^2+7=16$ $a_4=4^2+7=23$ $a_5=5^2+7=32$ $a_6=6^2+7=43$ Hence $\sum_{n=1}^6(n^2+7)=8+11+16+23+32+43=133$
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