Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Standardized Test Practice - Short Response - Page 791: 14


See below

Work Step by Step

The margin of error formula is $M=\pm \frac{1}{\sqrt n}$ Find $n=\frac{1}{m^2}\\ \rightarrow n=\pm \frac{1}{(\pm 0.02)^2}=2500$ Hence, $M=\pm 0.02$ Since the interval is $[49,51]$, we may not know whether the exact percentage is higher than 50.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.