Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - 11.1 Find Measures of Central Tendency and Dispersion - 11.1 Exercises - Mixed Review - Page 749: 34


58.5; 9240

Work Step by Step

Plugging in the given values of x, we find: $$f(3.8)=3.8(15.4)=58.5 \\ f(600)= (15.4)(600)= 9240$$
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