Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 1, Equations and Inequalities - Standardized Test Preparation - Short Response - Page 68: 9


$2 in.^2$

Work Step by Step

We have 1 pica $= \frac{1}{6}$ in. The area of a rectangle is given by: $A=l\times w$ Plug in the values: $A=9 \times 8 =72 pica^2$ Convert: $72 pica^2 = 72(\frac{1}{6})^2=2 in.^2$
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