Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - Get Ready: 19

Answer

$81b^6$

Work Step by Step

We start with the given expression: $(9b^3)^2$ To raise a product to a power, we raise each factor to the power and multiply: $9^2(b^3)^2$ We simplify the constant power: $81(b^3)^2$ To raise a power to a power, we multiply the exponents: $81b^{3\times2}=81b^6$
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