Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-1 Adding and Subtracting Polynomials - Mixed Review: 67

Answer

$-10t^6$

Work Step by Step

We start with the given expression: $(2t^4)(-5t^2)$ We rearrange and regroup the factors by like terms: $(2\times-5)(t^2t^4)$ We multiply the constants: $-10t^2t^4$ To multiply powers with the same base, we add the exponents: $-10t^{2+4}=-10t^6$
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