Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Practice and Problem-Solving Exercises: 23

Answer

$\dfrac{3b^7}{a^6c^8}$

Work Step by Step

RECALL: (i) $a^m \cdot a^n = a^{m+n}$ (ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ (iii) $a^0=1, a\ne0$ Use the rules above to have: $=\dfrac{12}{4} \cdot a^{-1-5}b^{6-(-1)}c^{-3-5} \\=3 \cdot a^{-6}b^{6+1}c^{-8} \\=3 \cdot \dfrac{1}{a^6} \cdot b^7 \cdot \dfrac{1}{c^8} \\=\dfrac{3b^7}{a^6c^8}$
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