Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-3 Multipying Powers with the Same Base - Practice and Problem-Solving Exercises - Page 429: 11



Work Step by Step

We start with the given expression: $(2)^{2}\times(2)^{7}\times(2)^{0}$ To multiply powers with the same base, we add the exponents. Therefore, $(2)^{2}\times(2)^{7}\times(2)^{0}=2^{2+7+0}=2^{9}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.