Answer
$2^{9}$
Work Step by Step
We start with the given expression: $(2)^{2}\times(2)^{7}\times(2)^{0}$
To multiply powers with the same base, we add the exponents.
Therefore, $(2)^{2}\times(2)^{7}\times(2)^{0}=2^{2+7+0}=2^{9}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-3 Multipying Powers with the Same Base - Practice and Problem-Solving Exercises - Page 429: 11
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