Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 5 - Linear Functions - 5-5 Standard Form - Practice and Problem-Solving Exercises: 11

Answer

$x$-intercept: $-\frac{20}{3}$ $y$-intercept: $4$

Work Step by Step

To find the $x$-intercept of an equation in standard form, we plug in $0$ for $y$, and solve for $x$. $3x-5(0)=-20$ We multiply: $3x+0=-20$ We apply the identity property of addition: $3x=-20$ We divide by $3$ on both sides of the equation: $x=-\frac{20}{3}$ To find the $y$-intercept of an equation in standard form, we plug in $0$ for $x$, and solve for $y$. $3(0)-5y=-20$ We multiply: $0-5y=-20$ We apply the identity property of addition: $-5y=-20$ We divide by $-5$ on both sides of the equation: $y=\frac{-20}{-5}$ We simplify: $y=4$
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