Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-7 Solving Proportions - Practice and Problem-Solving Exercises - Page 129: 57



Work Step by Step

$\frac{5x}{x^3+5}=\frac{5}{x^2-7}$ cross multiply $5x(x^2-7)=5(x^3+5)$ distributive property $5x^3-35x=5x^3+25$ subtract $5x^3$ from each side $5x^3-35x-5x^3=5x^3+25-5x^3$ combine like terms $-35x=25$ divide both sides by -35 $-35x\div-35=25\div-35$ simplify $x=-\frac{5}{7}$
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