Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - 12-8 Probability of Compound Events - Practice and Problem-Solving Exercises - Page 769: 33



Work Step by Step

You do not replace the coins, so the events are dependent: P(nickel)=$\frac{1}{9}$-1 of the 9 coins are dimes- P(nickel after nickel)=$\frac{0}{8}$=0 -0 of the 8 remaining coins are nickels- Probability: P(nickel then nickel)=P(nickel) $\times$ P(nickel after nickel) P(nickel then nickel)=$\frac{1}{9}$ $\times$ 0 P(nickel then nickel)=0
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