Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 623: 8

Answer

$t=49$

Work Step by Step

$Given,$ $\sqrt t + 2=9$ $\sqrt t + 2-2=9-2$ $\sqrt t=7$ Squaring,we get: $t=49$ We need to check by putting the obtained value in the original equation : $L.H.S=\sqrt 49 + 2=7 + 2=9=R.H.S$ Hence, $t=49$ is a valid solution
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