Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - Get Ready! - Page 77: 9



Work Step by Step

We need a common denominator (bottom of the fraction) to subtract the numerators (tops of the fractions). Thus, we multiply $\frac{3}{4}$ by $\frac{5}{5}$ to get $\frac{15}{20}$ and multiply $\frac{3}{10}$ by $\frac{2}{2}$ to get $\frac{6}{20}$. (This is legal because $\frac{2}{2}$ and $\frac{5}{5}$ are equal to one). We now have: $\frac{6}{20}$-$\frac{15}{20}$=-$\frac{9}{20}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.