## Algebra 1: Common Core (15th Edition)

$b=29$
In order to solve this algebraic expression, we must isolate the variable. A variable is the letter in the problem (for instance, in the equation 2x=10, x is the variable). Because multiplication and division are inverse operations (they cancel each other out), we know we must divide when a number is being multiplied by the variable and multiply when the variable is being divided by a number. In the equation $5b=145$, we must get rid of the 5, which the variable is being multiplied by, in order to solve. Thus, we divide both sides by 5 to find that $b=29$. We plug 29 in for b and confirm that our answer is, indeed, correct.