Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Got It? - Page 765: 4

Answer

$455$

Work Step by Step

$_{n}C_{r}$= $_{15}C_{3}$= $\frac{15!}{3!\times(15-3)!}$= $\frac{15\times14\times13\times12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1}{3\times2\times1\times(12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1}$= $455$
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