Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-5 Solving Rational Equations - Practice and Problem-Solving Exercises - Page 697: 58

Answer

$=\frac{-4k-61}{(k-4)(k+10)}$

Work Step by Step

$\frac{k-11}{k^2+6k-40}-\frac{5}{k-4}$ $=\frac{k-11}{(k-4)(k+10)}-\frac{5}{k-4}$ $=\frac{(k-11)-5(k+10)}{(k-4)(k+10)}$ $=\frac{-4k-61}{(k-4)(k+10)}$
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