Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 638: 61


$f=\pm 2$

Work Step by Step

We are given: $2f^2-8=0$ $f=\frac{-0\pm \sqrt 0^2-4.2.(-8)}{2.2}$ $f=\frac{\pm8}{4}$ $f=\pm 2$ There are two solutions: $f=\pm 2$.
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