Answer
a) Sum of (112)x_{y}3 = 35
product of (210)x_{y}3 = 294
35 into base 3 =(1022)x_{y}3
294 into base 3=(101220)x_{y}3
Work Step by Step
(112)x_{y}3 =1\times 3x^{y}2+1\times3x^{y}1+2\times3x^{y}0 =14
(210)x_{y}3 =2\times3x^{y}2+1\times3x^{y}1+0\times3x^{y}0 =21
sum=(112)x_{y}3+(210)x_{y}3
=35
product=(112)x_{y}3\times(210x_{y}3)=294
35 into base 3:
35 =3\times11+2
11 =3\times3+2
3 =3\times1+0
1 =3\times0+1
Base is (1022)x_{y}3
294 into base 3
294 =3\times98+0
98 =3\times32+2
32 =3\times10+2
10 =3\times3+1
3 =3\times1+0
1 =3\times0+1
Base is (101220)x_{y}3
