Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley
ISBN 10: 1118412931
ISBN 13: 978-1-11841-293-0

Chapter 1 - Problems: Developing Engineering Skills - Page 35: 1.52

Answer

We know that , T(degree C) = T(K) – 273.15 --> T(K) = T( degree C) + 273.15 T water (K) = 24 degree C + 273.15 = 297.15 K Next to solve for temperature in degree R T(degree R) = 1.8T(K) Twater (degree R) = (1.8)(297.15 K) = 534.87 degree R Finally, to solve for temperatures in degree F T(degree F) = T(degree R) – 459.67 Twater (degree F) = 534.87 degree R – 459.67 = 75.2 degree F

Work Step by Step

We know that , T(degree C) = T(K) – 273.15 --> T(K) = T( degree C) + 273.15 T water (K) = 24 degree C + 273.15 = 297.15 K Next to solve for temperature in degree R T(degree R) = 1.8T(K) Twater (degree R) = (1.8)(297.15 K) = 534.87 degree R Finally, to solve for temperatures in degree F T(degree F) = T(degree R) – 459.67 Twater (degree F) = 534.87 degree R – 459.67 = 75.2 degree F
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.

GradeSaver will pay $15 for your literature essays
GradeSaver will pay $25 for your college application essays
GradeSaver will pay $50 for your graduate school essays – Law, Business, or Medical
GradeSaver will pay $10 for your Community Note contributions
GradeSaver will pay $500 for your Textbook Answer contributions