Shigley's Mechanical Engineering Design 10th Edition

Published by McGraw-Hill Education
ISBN 10: 0073398209
ISBN 13: 978-0-07339-820-4

Chapter 14 - Problems - Page 773: 14-6

Answer

Therefore facewidth should be kept = 28mm from table 13-2

Work Step by Step

$Pitch Diameter, d=N ∗ m=20∗2=40 mm$ where, N = number of teeth m= module $Lewis form factor, Y = 0.322$ ; for 20 teeth with 20degree pressure angle $Pitch line velocity, V=(pi ∗ d ∗ n)/60$ ; where n = speed in rpm therefore $V=(3.14∗40∗0.001∗200)/60=0.419 m/s$ $Velocity Factor, K=(6.1+V)/6.1$ ; for cut or milled profile therefore $K=(6.1+0.419)/6.1=1.069$ $Tangential load, W=(60000∗h)/(pi ∗ d ∗ n)$ ; where h is power in kW therefore $W=(60000∗0.5)/(3.14∗40∗200)=1.194 kN =1194 N$ $Facewidth,F=(K∗W)/(sigma ∗ m ∗ Y)$ ; where sigma is bending stress $Facewidth,F=(1.069∗1194)/(75∗2∗0.322)$ $Facewidth,F=26.4 mm$ Therefore facewidth should be kept = 28mm from table 13-2
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