Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.3 - Problems - Power and Enery - Page 36: P1.30


$433 per kWhr

Work Step by Step

$9V\times50mA\times10hr = 0.0045kWhr$ $\$1.95\div0.0045kWhr=\$433.33\ per\ kWhr$
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