Answer
See explanation
Work Step by Step
Data size = 50 KB = 50 * 1024 bytes = 51200 bytes
One sector can store 1024 characters so the number of sectors required to store 51200 characters will be-
$\frac{51200}{1024} = 50$ sectors
Now there are 20 sectors in one track so we will need $\frac{50}{20}$ = 2.5 tracks.
So the file spans 3 tracks.
For fastest access time we should:
To minimize access time, place the file:
- on the same surface (to avoid switching heads between surfaces)
- on consecutive tracks (to reduce arm movement)
- near the middle of the disk (to minimize average seek time from other locations)
- aligned with rotational timing (start at the beginning of a track to avoid waiting for rotation).
