Computer Science: An Overview: Global Edition (12th Edition)

Published by Pearson Higher Education
ISBN 10: 1292061162
ISBN 13: 978-1-29206-116-0

Chapter 2 - Data Manipulation - Chapter Review Problems - Page 131: 4

Answer

\( \begin{align*} \text{Address 00-05} & : 34, 17, 50, 2, 192, 0 \end{align*} \)

Work Step by Step

To determine the value stored in memory cells 00 through 05, we interpret the contents of each memory address according to the given bit patterns: - Address 00: 22 - Address 01: 11 - Address 02: 32 - Address 03: 02 - Address 04: C0 - Address 05: 00 Converting each bit pattern to decimal: - Address 00: \( 22_{hex} = 34_{dec} \) - Address 01: \( 11_{hex} = 17_{dec} \) - Address 02: \( 32_{hex} = 50_{dec} \) - Address 03: \( 02_{hex} = 2_{dec} \) - Address 04: \( C0_{hex} = 192_{dec} \) - Address 05: \( 00_{hex} = 0_{dec} \) Therefore, the value stored in memory cells 00 through 05 in decimal representation is: \[ \begin{align*} \text{Address 00-05} & : 34, 17, 50, 2, 192, 0 \end{align*} \]
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