Answer
e. \( \frac{15}{16} \)
Work Step by Step
This value, \( \frac{15}{16}\), cannot be represented accurately in the given floating-point format because it involves a fraction that does not have an exact binary representation. This means that when converted into binary for storage in the floating-point format, it will likely be approximated, leading to potential loss of precision.
15/16 = 0.9375
To represent this, we’d need a significand of 1.111 and exponent of -1. But with only 4 bits of mantissa, we can't encode exactly 0.9375 in normalized form