University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 6 - Work and Kinetic Energy - Problems - Exercises - Page 195: 6.25

Answer

F = 48.0 N

Work Step by Step

$W = KE_2 - KE_1$ $F~d = \frac{1}{2}mv_2^2-\frac{1}{2}mv_1^2$ $F = \frac{m(v_2^2-v_1^2)}{2d}$ $F = \frac{(12.00~kg)((6.00~m/s)^2-(4.00)^2)}{(2)(2.50~m)}$ $F = 48.0~N$
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