Answer
W = 135 J
Work Step by Step
We can find the magnitude of the force.
$F = \sqrt{(-68.0~N)^2+(36.0~N)^2}$
$F = 76.9~N$
We can find the angle $\alpha$ above the (-x)-axis.
$tan(\alpha) = \frac{36.0~N}{68.0~N}$
$\alpha = arctan(\frac{36.0~N}{68.0~N})$
$\alpha = 27.9^{\circ}$
We can find the angle $\theta$ between the force vector and the displacement vector.
$\theta = 27.9^{\circ}+60.0^{\circ}$
$\theta = 87.9^{\circ}$
We can find the work done by the force.
$W = F~d~cos(\theta)$
$W = (76.9~N)(48.0~m)~cos(87.9^{\circ})$
$W = 135~J$
