Answer
(a) v = 43.2 m/s
(b) v = 101 m/s
Work Step by Step
(a) $KE_1 + W = KE_2$
$0 + mg~d = \frac{1}{2}mv^2$
$v^2 = 2gd$
$v = \sqrt{(2)(9.8~m/s^2)(95.0~m)}$
$v = 43.2~m/s$
(b) $KE_1 + W = KE_2$
$ \frac{1}{2}mv^2 - mg~d = 0$
$v^2 = 2gd$
$v = \sqrt{2gd}$
$v = \sqrt{(2)(9.80~m/s^2)(525~m)}$
$v = 101~m/s$
