University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 28 - Sources of Magnetic Field - Problems - Discussion Questions - Page 947: Q28.15

Answer

$\frac{J}{T}= A \cdot m^2 $

Work Step by Step

$$\frac{J}{T}=\frac{N \cdot m}{N/(A \cdot m)} $$ $$=(N \cdot m)\frac{A \cdot m}{N} = A \cdot m^2 $$
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