University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 21 - Electric Charge and Electric Field - Problems - Exercises - Page 713: 21.7

Answer

3.7 km

Work Step by Step

From Coulomb's law, $F = k\frac{q_1 q_2}{r^2}$ $\implies r = \sqrt{k\frac{q_1 q_2}{F}} = \sqrt{(9 \times 10^9)\frac{(1)^2}{650}} = 3.7 \times 10^3 \ m = 3.7 \ km$
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