University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 21 - Electric Charge and Electric Field - Problems - Exercises - Page 713: 21.2

Answer

$1.25 \times 10^{19}$

Work Step by Step

The rate of charge flow is known as current, and we can represent it as $i$. For a given charge $q$ and a time $t$, we have $ q = it$. We also know that charge is quantized, which means that for integral values of $n$, $q =ne$ where $e$ is the charge of an electron. Accordingly, we have . . . $ ne = it \implies n = \frac{it}{e} = \frac{(20000)(100\times10^{-6})}{1.6\times 10^{-19}} = 1.25 \times 10^{19}$
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