University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 21 - Electric Charge and Electric Field - Problems - Exercises - Page 713: 21.5

Answer

1.3 nC

Work Step by Step

The total charge $Q$ is $Ne$, where $N$ is the number of ions and $e = 1.6 \times 10^{-19} C$. The number of ions $N = (5.6 \times 10^{11})(1.5\times 10^{-2}) = 8.4 \times 10^9$ ions. The total charge $Q = Ne = (8.4 \times 10^9)(1.6 \times 10^{-19}) = 1.3 \times 10^-9 \ C = 1.3 \ nC.$
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