Answer
(d) With the rapid expansion, the expanding gas does work with no heat input, so the internal energy and temperature of the gas decrease.
Work Step by Step
Some $N_2O$ are condensed during this process because the gas rushed out from the cylinder rapidly. This made the temperature decrease immediately, causing some of it to condense. This makes $Q = 0$ meaning no heat is added to the system but the work is done to the gas.
So, (d) is correct which is "With the rapid expansion,
the expanding gas does work with no heat input, so the internal
energy and temperature of the gas decrease"
