Answer
(c) 1830 psi
Work Step by Step
The gas is cooled at constant volume, the formula becomes
$\frac{p_1}{T_1} = \frac{p_2}{T_2}$
$(T_2) \frac{p_1}{T_1} = p_2$
$ p_2 = (268K) \frac{2000 psi}{293 K}$
$ p_2 = 1829.4 psi$.
This makes choice (c) the right answer as we round it off to nearest ten, which is $1830 psi$
