Answer
(a) $V = 0.21 m^3$
Work Step by Step
The mole of the gas is the same on Nitrogen and Oxygen
$n = \frac{m}{M} $
$n = \frac{1700 g}{44 g/mol} $
$n = 38.6 mol$
Total pressure must be added with atmospheric pressure
$p = 50 psi + 14.7 psi$
$p = 64.7 psi$ Now change to atm
$p = (64.7 psi )(6895 atm/psi)$
$p =4.46 \times 10^5 atm$
$V = nRT/p$
$V = \frac{(38.6 mol)(8.3145 J/mol.K)(293 K) }{4.46 \times 10^5 atm} $
$V = 0.21 m^3$ which is choice (a)
