Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1152: 12

Answer

(a) $3\times 10^{26}$ (b) $800nm$

Work Step by Step

(a) We can find the number of nucleons as follows: $M=\frac{W}{g}$ $\implies m=\frac{1lb(\frac{4.448lb}{1lb})}{9.8m/s^2}$ $m=0.454Kg$ Now, the number of nucleons is given as $n=\frac{M}{m}$ We plug in the known values to obtain: $n=\frac{0.454Kg}{14.6\times 10^{27}Kg}$ $n=3\times 10^{26}$ (b) We can find the required radius as $r=(1.2\times 10^{-15})(3\times 10^{26})^{\frac{1}{3}}$ $r=800\times 10^{-9}m=800nm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.