Answer
$1s^2 2s^2 2p^3$
Work Step by Step
The nitrogen has 7 electrons in its outermost shell in the ground state. The first 2 electrons are placed in the 1s subshell. The other two electrons occupy the 2s subshell, while the remaining 3 electrons occupy the 2p subshell. Thus, the electronic configuration of nitrogen in the ground state is given as
$1s^2 2s^2 2p^3$
