Answer
$n=3$
$l=1$
$m_l=-1,0,1$
$m_s=\frac{-1}{2}\space and \frac{+1}{2}$
(We can use these values to write out the 6 different unique combinations of the four quantum numbers.)
Work Step by Step
We know that for the 3p subshell
$n=3$ and for the p subshell l=1
We also know that for $n=3$ and $l=1$ the possible values of $m_l$ are $m_l=-1,0,1$ and $m_s=\frac{-1}{2}\space and \frac{+1}{2}$
Hence, the required set of the four quantum numbers is:
$n=3$
$l=1$
$m_l=-1,0,1$
$m_s=\frac{-1}{2}\space and \frac{+1}{2}$
(We can use these values to write out the 6 different unique combinations of the four quantum numbers.)
