Answer
a) $f_{standard}$ = 1.7X $10^{14}$ Hz
$f_{halogen}$ = 1.99 X $10^{14}$ Hz
b) 1.17
c)halogen bulb
Work Step by Step
a
The Wien's law says that
frequency is related to temperature as
$f_{peak}$ = 5.88 X $10^{10}$ X T.
For light bulb,
$T_{A}$ = 2900 K
$f_{peak}$ = 5.88 X $10^{10}$ X T
$f_{std}$ = 5.88 X $10^{10}$ X 2900 = 1.7X $10^{14}$ Hz.
For halogen bulb,
$T_{B}$ = 3400 K
$f_{peak}$ = 5.88 X $10^{10}$ X T
$f_{hal}$ = 5.88 X $10^{10}$ X 3400 = 1.99 X $10^{14}$ Hz.
b
$f_{std}$ = 1.7X $10^{14}$ Hz
$f_{hal}$ = 1.99 X $10^{14}$ Hz
The ratio is
$\dfrac{f_{hal}}{f_{std}}$ = $\dfrac{1.99}{1.7}$ = 1.17.
c
The halogen bulb has a higher frequency than the standard light bulb, and it is closer to the sensitive frequency for the eyes.
