Answer
(a) $1.68\times 10^{14}Hz$
(b) infrared
Work Step by Step
(a) We can determine the frequency for maximum radiation as:
$f_{peak}=5.88\times 10^{10}\times T$
We plug in the known values to obtain:
$f_{peak}=5.88\times 10^{10}\times 2850=1.68\times 10^{14}Hz$
(b) We know that energy is directly proportional to frequency. The frequency of infrared radiation is larger compared to visible light, so the energy of infrared radiation is larger as well.