Answer
(a) $4.795\times 10^{13}Hz$
(b) $3.18\times 10^{-20}J$
Work Step by Step
(a) We can find the required frequency as
$f=\frac{1}{2\pi}\sqrt{\frac{K}{m}}$
We plug in the known values to obtain:
$f=\frac{1}{2\pi}\sqrt{\frac{1215}{1.340\times 10^{-26}}}$
$f=4.795\times 10^{13}Hz$
(b) We know that
$E=hf$
We plug in the known values to obtain:
$E=(6.625\times 10^{-34})(4.795\times 10^{13})$
$E=3.18\times 10^{-20}J$
