Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 3 - Vectors in Physics - Problems and Conceptual Exercises - Page 77: 11

Answer

$d=1.5~A$

Work Step by Step

See the figure: $\sin{52.25}^{\circ}=\frac{\frac{d}{2}}{0.96~A}$ $d=2(0.96~A)(\sin{52.25}^{\circ})$ $d=1.5~A$
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