Answer
(a) The vector $A$
(b) The vector $B$
Work Step by Step
(a)
$A_x=50\times cos~0^{\circ}=50$
$B_x=120\times cos~(-70^{\circ})=41$. So: $|A_x|\gt|B_x|$
(b)
$A_y=50\times sin~0^{\circ}=0$
$B_y=120\times sin~(-70^{\circ})=-112.7$. So: $|B_y|\gt|A_y|$
