Answer
(a) $\theta=325.9^{\circ}$ or $-34.14^{\circ}$
(b) $17~m$
(c) The direction remains the same, but the magnitude is doubled.
Work Step by Step
(a) $tan~\theta=\frac{r_{y}}{r_{x}}$
$\theta=tan^{-1}(\frac{r_{y}}{r_{x}})=tan^{-1}(\frac{-9.5~m}{14~m})=145.9°~or~325.9^{\circ}$. According to the figure:
$\theta=325.9^{\circ}$
(b) $r=\sqrt {(r_{x})^2+(r_{y})^2}=\sqrt {(14~m)^2+(-9.5~m)^2}=17~m$
(c) See the Problems and Conceptual Exercises 1 (page 76).
