Answer
$0.33c$
Work Step by Step
We know that
$v_{23}=\frac{v_{21}+v_{13}}{1+\frac{v_{21}v_{13}}{c^2}}$
We plug in the known values to obtain:
$0.866c=\frac{v_{21}+0.75c}{1+\frac{v_{21}(0.75c)}{c^2}}$
This simplifies to:
$v_{21}=0.33c$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1044: 85
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