Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1044: 84

Answer

$2.0s$

Work Step by Step

We know that $\Delta t=\frac{\Delta t_{\circ}}{\sqrt{1-\frac{v^2}{c^2}}}$ We plug in the known values to obtain: $\Delta t=\frac{1.00s}{\sqrt{1-(\frac{\frac{\sqrt3 c}{2}}{c})^2}}$ This simplifies to: $\Delta t=2.0s$
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