Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 29 - Relativity - Problems and Conceptual Exercises - Page 1044: 86

Answer

(a) $16m$ (b) $110m$

Work Step by Step

(a) We calculate the radius for non-relativistic momentum as $R=\frac{p}{qb}$ $\implies R=\frac{mv}{qb}$ $R=\frac{(1.673\times 10^{-27})(0.99)(3.00\times 10^{8})}{(1.60\times 10^{-19})(0.20)}$ $R=16m$ (b) Now the radius for the relativistic momentum can be determined as $R=\frac{mv}{qb\sqrt{1-v^2/c^2}}$ We plug in the known values to obtain: $R=\frac{(1.673\times 10^{-27})(0.99)(3.00\times 10^8)}{(1.60\times 10^{-19})(0.20)\sqrt{1-(0.99)^2}}$ $R=110m$
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